# How Many Grams (of Mass m) of Glucose are in 345 ml of a 5.50% (m/v) Glucose Solution?: Dealing with Units and Percentage Accurately ## How Many Grams (of Mass m) of Glucose are in 345 ml of a 5.50% (m/v) Glucose Solution?

Have you ever wondered how to calculate the mass of glucose in a solution? In this article, I’ll walk you through the steps to determine how many grams of glucose are present in a given volume of a 5.50% (m/v) glucose solution. Understanding this calculation can be useful in various scientific and medical fields.

Let’s consider an example where we have 345 ml of a 5.50% (m/v) glucose solution. The concentration is expressed as a percentage by mass per volume, which means that for every 100 ml of the solution, there are 5.50 grams of glucose dissolved in it.

To find the mass of glucose in our given volume, we need to use the equation:

Mass of Glucose = Volume of Solution (in mL) × Concentration (% m/v)

Plugging in our values, we get:

Mass of Glucose = 345 ml × 5.50%

Simplifying further:

Mass of Glucose = 345 ml × 0.055

By multiplying these numbers together, we can find the answer and determine how many grams of glucose are present in our specified volume.

## Calculating the Mass of Glucose in a Solution

To determine the mass of glucose in a solution, we can use the formula:

Mass of glucose = Volume of solution (in mL) × Concentration of glucose (in g/mL)

In this case, we are given that the volume of the solution is 345 mL and the glucose concentration is 5.50% (m/v). Let’s break down the calculation step by step.

1. Convert the concentration from percentage to grams per milliliter:
• 5.50% (m/v) means 5.50 grams of glucose per 100 milliliters.
• To convert it to grams per milliliter, we divide by 100: 5.50 g/100 mL = 0.055 g/mL.
1. Multiply the volume of the solution by the concentration:
• Mass of glucose = 345 mL × 0.055 g/mL
• Mass of glucose = 18.975 g

So, there are approximately 18.975 grams of glucose in a 345 mL solution with a concentration of 5.50% (m/v).

It’s important to note that when calculating concentrations in solutions, it’s essential to account for both volume and concentration units to ensure accurate results.

## Understanding the Given Parameters

To solve the problem of calculating the mass of glucose in a given solution, we need to understand and analyze the parameters provided. Let’s break down each component:

1. Volume (V): The volume of the solution is given as 345 ml. This tells us how much liquid is present in the sample.
2. Concentration (5.50% m/v): The concentration is expressed as a percentage by mass per volume (% m/v). In this case, it represents the amount of glucose dissolved in 100 ml of the solution. So, for every 100 ml of the solution, there are 5.50 grams of glucose.
3. Glucose Mass (m): We are tasked with determining the mass of glucose present in the given volume (345 ml) of the solution.

Now that we clearly understand these parameters, we can proceed with solving for the mass of glucose.

To calculate this, we’ll use a simple equation:

Mass = Volume × Concentration

Let’s substitute our values into this equation:

Mass = 345 ml × (5.50 g/100 ml)

Simplifying further:

Mass = (345 × 5.50) / 100

Calculating this expression yields our desired result:

Mass = 18.975 g

Therefore, approximately 18.975 grams of glucose are in a 345 ml sample of a 5.50% m/v glucose solution.

Simon is an experienced cook and dedicated father who has been in the foodservice industry for over a decade. A culinary school graduate, Simon has refined and perfected his skills, both in the kitchen and at home as a father of two. He understands flavor combinations like few others do and is able to create amazing dishes with ease. In addition to his cooking skills, Simon also has the unique ability to connect with his two children. Working in kitchens around the world, he has learned how to juggle parenting duties while still finding time for himself and his family. Whether it’s reading stories with them or teaching them how to make their own meals, Simon puts a premium on teaching his children valuable life lessons that will last them well into adulthood.