# How Many Moles of Na+ are Present in 343 ml of a 1.27 m Solution of Na2SO4?: Exploring the Chemistry Formula

## How Many Moles of Na+ are Present in 343 ml of a 1.27 m Solution of Na2SO4?

Have you ever wondered how to calculate the number of moles of Na+ in a given solution? Well, today I’ll walk you through the process step by step. In this particular case, we have a 1.27 M (molar) solution of Na2SO4 with a volume of 343 mL. The question at hand is: How many moles of Na+ are present in this solution?

To find the number of moles, we need to use the formula:

moles = concentration (M) x volume (L)

In our scenario, the concentration is given as 1.27 M and the volume is 343 mL. However, before we proceed with the calculation, it’s important to convert milliliters (mL) to liters (L). Since there are 1000 mL in one liter, our volume becomes 0.343 L.

Now, let’s plug in these values into our formula:

moles = 1.27 M x 0.343 L

Performing this calculation gives us the answer:

moles = 0.43561 mol

Therefore, there are approximately 0.436 moles of Na+ present in a 343 mL sample of a 1.27 M solution of Na2SO4.

Understanding how to determine the number of moles in a given solution allows us to analyze chemical properties on a deeper level and make accurate calculations for various scientific applications.

## Calculating Moles of Na+ in a Solution

When determining the number of moles of Na+ present in a solution, we need to consider the concentration and volume of the solution. In this case, we are given that the solution is 1.27 M (molar) and has a volume of 343 mL.

To calculate the moles of Na+, we can use the formula:

moles = concentration (M) x volume (L)

First, let’s convert the volume from milliliters to liters by dividing it by 1000:

volume = 343 mL ÷ 1000 = 0.343 L

Now, we can plug in the values into our formula:

moles = 1.27 M x 0.343 L

Calculating this gives us:

moles = 0.43481 mol Na+

So, there are approximately 0.435 moles of Na+ present in a 343 mL solution with a concentration of 1.27 M.

It’s important to note that when calculating moles, we only consider the desired substance (in this case, Na+) and not any other components like SO4^2-. Additionally, make sure to double-check your calculations and units to ensure accurate results.

## Determining the Molar Mass of Na2SO4

To calculate the number of moles of Na+ present in a given volume of a 1.27 M solution of Na2SO4, we first need to determine the molar mass of Na2SO4. The molar mass is the sum of the atomic masses of all the elements in a compound.

In the case of Na2SO4, it consists of two sodium atoms (Na), one sulfur atom (S), and four oxygen atoms (O). To find their respective atomic masses, we can refer to the periodic table:

• Sodium (Na) has an atomic mass of 22.99 g/mol.
• Sulfur (S) has an atomic mass of 32.07 g/mol.
• Oxygen (O) has an atomic mass of 16.00 g/mol.

Now, let’s calculate the molar mass:

Molar Mass(Na2SO4) = (2 * Atomic Mass(Na)) + Atomic Mass(S) + (4 * Atomic Mass(O))

= (2 * 22.99 g/mol) + 32.07 g/mol + (4 * 16.00 g/mol)

= 46.00 g/mol + 32.07 g/mol + 64.00 g/mol

= 142.07 g/mol

Therefore, the molar mass of Na2SO4 is 142.07 grams per mole.

Now that we know the molar mass, we can proceed to calculate how many moles are present in a given volume using its concentration.

The concentration is expressed as 1.27 M, which means there are 1.27 moles per liter (1000 ml) or 0.00127 moles per milliliter (ml).

In this case, we have a volume of 343 ml. To find the number of moles, we can use the following conversion:

Number of moles = Concentration * Volume in liters

= 1.27 mol/L * (343 ml / 1000)

= 1.27 mol/L * 0.343 L

≈ 0.43561 moles

Therefore, there are approximately 0.43561 moles of Na+ present in a 343 ml solution with a concentration of 1.27 M Na2SO4.

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