How Many Moles of Nacl are Present in a Solution With a Molarity of 8.59 m and a Volume of 125 ml?: Understanding and Utilizing the Appropriate Formula

How Many Moles of Nacl are Present in a Solution With a Molarity of 8.59 m and a Volume of 125 ml?

Have you ever wondered how to calculate the number of moles of NaCl in a solution with a given molarity and volume? Well, today I’ll be diving into this intriguing topic. Let’s say we have a solution with a molarity of 8.59 M and a volume of 125 mL. The question is: how many moles of NaCl are present in this solution?

To find the answer, we can use the formula n = M x V, where n represents the number of moles, M is the molarity, and V is the volume in liters. In this case, we need to convert the volume from milliliters to liters by dividing it by 1000: 125 mL ÷ 1000 = 0.125 L.

Now that we have all our values ready let’s plug them into the formula: n = 8.59 M x 0.125 L. Multiplying these two values gives us an impressive result of 1.07375 moles of NaCl present in our solution.

Calculating the Number of Moles in a Solution

When working with solutions, understanding the number of moles present is crucial for many chemical calculations. In this section, I’ll guide you through calculating the number of moles in a solution.

First, let’s consider a solution with a molarity of 8.59 M and a volume of 125 mL. The molarity tells us the number of moles of solute per liter of solution. However, since our volume is in milliliters, we need to convert it to liters before proceeding with the calculation.

To convert 125 mL to liters, we divide by 1000:

125 mL / 1000 = 0.125 L

Now that we have our volume in liters, we can calculate the number of moles using the formula:

Number of Moles = Molarity x Volume (in liters)

Plugging in our values:

Number of Moles = 8.59 M x 0.125 L

Calculating this expression gives us:

Number of Moles = 1.074375 moles

So, approximately 1.074375 moles of NaCl are present in the given solution.

Understanding Molarity and Volume

When working with solutions, it’s important to understand molarity and volume clearly. These two concepts are crucial in determining the amount of substance present in a solution. Let’s break down these terms and explore their significance.

Molarity: Molarity is defined as the number of moles of solute per liter of solution. It is denoted by the symbol ‘M’ and is commonly expressed in moles per liter (mol/L). In our case, we are dealing with a solution with a molarity of 8.59 M, meaning that 8.59 moles of solute (NaCl) are present for every liter of solution.

Volume: Volume refers to the amount of space a substance or mixture occupies. In the context of our problem, we have a solution with a volume of 125 mL (milliliters). It’s worth noting that when dealing with molar calculations, it is essential to ensure that all units are consistent. Therefore, we need to convert milliliters to liters by dividing the volume by 1000:

125 mL ÷ 1000 = 0.125 L

Now that we have established both the molarity and volume values, we can determine how many moles of NaCl are present in our solution.

To calculate this value, we use the formula:

moles = molarity × volume

Plugging in our given values:

moles = 8.59 M × 0.125 L = 1.07375 moles

Therefore, approximately 1.07 moles of NaCl are present in the given solution.

Final Thoughts

So there you have it! With a molarity of 8.59 M and a volume of 125 mL (or 0.125 L), we can confidently conclude that approximately 1.07375 moles of NaCl are dissolved in this solution.