How Many Moles of Nacl Are Present in A Solution With A Molarity of 8.59m and 125 Ml of Solution? Molarity and Volume Calculation

how many moles of nacl are present in a solution with a molarity of 8.59m and 125 ml of solution?

Have you ever wondered how to calculate the number of moles of NaCl in a solution with a given molarity and volume? Well, look no further! In this article, I’ll provide a step-by-step guide on determining the number of moles of NaCl present in a solution.

To start off, let’s consider an example where we have a solution with a molarity of 8.59 M and a volume of 125 mL. The key to finding the number of moles is understanding that molarity represents the number of moles per liter (mol/L).

To calculate the number of moles in our given solution, we first need to convert the volume from milliliters to liters. Since there are 1000 mL in one liter, we can divide our initial volume by 1000:

125 mL / 1000 = 0.125 L

Now that we have our volume in liters, we can multiply it by the molarity to find the number of moles:

0.125 L * 8.59 mol/L = 1.07375 mol

How Many Moles of Nacl Are Present in A Solution With A Molarity of 8.59m and 125 Ml of Solution?

Molarity and moles are important concepts in chemistry that help us quantify the concentration of a substance in a solution. Let’s dive deeper into understanding these terms.

Molarity: Molarity, represented by the symbol M, is a unit of concentration. It tells us the number of moles of solute dissolved per liter of solution. In other words, it measures how much solute is present in a given volume of solution.

To calculate molarity, we use the formula:

Molarity (M) = Moles of Solute / Volume of Solution (in liters)

Moles: A mole is a unit used to measure the amount of substance. It represents Avogadro’s number, which is approximately 6.022 × 10^23 particles (atoms, molecules, ions) in one mole.

To calculate moles, we can rearrange the molarity formula as follows:

Moles = Molarity x Volume (in liters)

Now let’s apply this knowledge to our example: finding out how many moles of NaCl are present in a solution with a molarity of 8.59 M and a volume of 125 mL.

Firstly, we need to convert the volume from milliliters to liters:

Volume = 125 mL ÷ 1000 = 0.125 L

Now we can use the formula to calculate moles:

Moles = 8.59 M x 0.125 L = **1.07375** moles

So there are approximately 1.07 moles of NaCl present in this solution.

Calculating the Number of Moles in a Solution

In this section, I’ll explain how to calculate the number of moles present in a solution with a given molarity and volume. This calculation is essential for understanding the concentration of solute particles in a solution.

To begin, let’s review some key concepts:

Molarity (M)

Molarity is a measurement of the concentration of a solute in a solution. It is defined as the number of moles of solute per liter of solution. The unit for molarity is moles per liter (mol/L) or simply M.

Volume (V)

Volume refers to the amount of space occupied by a substance. In our case, it represents the total volume of the solution under consideration. This can be measured in milliliters (mL), liters (L), or any other suitable unit.

To calculate the number of moles in a solution, we can use the following formula:

Number of Moles = Molarity × Volume

Let’s apply this formula to our example:

Given:

  • Molarity = 8.59 M
  • Volume = 125 mL

First, we need to convert the volume from milliliters to liters by dividing it by 1000:

Volume = 125 mL ÷ 1000 = 0.125 L

Now we can plug these values into our formula:

Number of Moles = 8.59 M × 0.125 L

Calculating this expression gives us the following:

Number of Moles ≈ 1.074 mol

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